CompTIA Linux+ XK0-005 (v7) Practice Question

Brace expansion produces the list 1 2 3 4 5 and attaches the prefix "Number_" to each element. The echo builtin then prints each resulting word, separating them with spaces. Therefore, the output is:

Number_1 Number_2 Number_3 Number_4 Number_5

The other options are incorrect because:

• Bash always expands the brace expression unless it is quoted, so the literal string with braces will not appear.
• Echo places a space between each argument, so the result is not a single concatenated word.
• The range ends at 5, so no sixth value is produced.