You must add a for loop that prints each filename on its own line without changing IFS or invoking external commands. Which loop meets the requirement?
IFS=$'\n'; for f in $(printf '%s\n' "${files[@]}"); do echo "$f"; done; unset IFS
When the expansion "${files[@]}" is placed inside double quotes, Bash passes each element of the array to the loop as a separate word, so every filename-spaces included-reaches the body intact. Using the same expansion without quotes subjects the result to word-splitting, so entries that contain spaces are broken into multiple words. Quoting "${files[*]}" joins all elements into a single word separated by the first character of IFS, so only one iteration occurs. The fourth option works around splitting by manipulating IFS and spawning printf, but the task explicitly forbids altering IFS or running external utilities. Therefore, the first loop is the only solution that satisfies all conditions.
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