Crucial Exams

CompTIA Linux+ XK0-006 (V8) Practice Question

A portable Bourne-shell (#!/bin/sh) start-up script must enable verbose output only when the variable $LOGLEVEL is exactly "DEBUG". The sysadmin tried the following code, which works under Bash but fails with the message ": ==: unexpected operator" on several older systems:

if [ "$LOGLEVEL" == "DEBUG" ]; then
    VERBOSE=true
fi

Which single change will make the condition POSIX-compliant and eliminate the error without introducing any non-standard syntax or external commands?

  • Replace the brackets with Bash's conditional expression:

    if [[ "$LOGLEVEL" == "DEBUG" ]]; then
    VERBOSE=true
fi```

  • Change the operator to a single equals sign:

    if [ "$LOGLEVEL" = "DEBUG" ]; then
    VERBOSE=true
fi```

  • Use the numeric comparison operator:

    if [ "$LOGLEVEL" -eq "DEBUG" ]; then
    VERBOSE=true
fi```

  • Escape the double-equals operator to force literal parsing:

    if [ "$LOGLEVEL" \== "DEBUG" ]; then
    VERBOSE=true
fi```
CompTIA Linux+ XK0-006 (V8)
Automation, Orchestration, and Scripting
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