Crucial Exams

CompTIA Linux+ XK0-006 (V8) Practice Question

A Linux administrator wants a loop in a Bash script to ignore any file whose name does not end with the extension .log and writes the following check:

if [[ $file != *.log ]]; then
    echo "Skipping $file"
fi

Which statement correctly describes what the != operator does inside the [[ … ]] test used here?

  • Inside [[ … ]], != interprets the right-hand operand as an unquoted glob pattern and is true when the left-hand string does not match that pattern.

  • != compares two strings while ignoring case differences, so DEBUG.LOG and debug.log are considered identical unless a special option is set.

  • != performs numeric inequality inside [[ … ]]; to compare strings you should use -ne instead.

  • When used inside [[ … ]], != applies an extended regular expression to the left-hand string, so a glob like *.log would be taken literally and never match.

CompTIA Linux+ XK0-006 (V8)
Automation, Orchestration, and Scripting
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